Divide 21 by g. Then, subtract 6.
2 answers:
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I took the test. Here's the right answer
Answer:
B.
Step-by-step explanation:
We have been given that the trapezoid shown in the attachment has been enlarged by a scale of 1.5. We are asked to find the area of the enlarged trapezoid.
The area of the original trapezoid is 36 square inches.
Since each side of the trapezoid is enlarged 1.5 times, so the area of new trapezoid would be 2.25 times greater than area of original trapezoid.
The area would be 2.25 times greater because area is product of sum of lengths of parallel sides and height.
Therefore, the area of the enlarged trapezoid would be and option B is the correct choice.
To find the z-score for a weight of 196 oz., use
A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.