Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
Answer: 46
Step-by-step explanation:
you just do 30 + 16
First, we get the area of each tile: (100 cm = 1m)
.20 m* .15 m = 0.03m^2
Then, we solve for the total area of the wall:
5m*3m= 15m^2
Then we divide
15/0.03 = 500 tiles
Answer:
The first one.
Step-by-step explanation:
For something to be considered to be a graph, every x value must have 1 y value. It does not matter if y values are the same, but you MUST make sure there is ONLY ONE of each value. So for example the second one wouldn't be a function because -5 appears twice for the x values, but with different y values. This would mean when graphed, it would fail the vertical line test (if you put a vertical line anywhere on the graph you will only get one point).
