19,7,and 61 im not sure about the last one
Answer:
18y^3 + 24y^5.
Step-by-step explanation:
6y^3(3 + 4y^2)
= 6*3 y^3 + 6*4 y^(3+2)
= 18y^3 + 24y^5.
Answer:
h(t) = -16t2 + 144
h(1) = -16(12) + 144 = 128 ft
h(2) = -16(22) + 144 = 80 ft
h(2) - h(1) = 80 - 128 = -48 ft
It fell 48 ft between t = 1 and t = 2 seconds.
It reaches the ground when h(t) = 0
0 = -16t2 + 144
t = √(144/16) s = 3s
It reaches the ground 3s after being dropped.
Step-by-step explanation:
Answer:
(-3,3)
Step-by-step explanation:
Using elimination:
Multiply the first equation by 8 and the second by 5 which equals
40x+56y=48
-40-60y=-60
Now you add them together
40x+(-40x)=0 so that crosses out
56y+(-60y)= -4y
48+(-60)=-12
You now have -4y=-12
Divide by -4
y=3
Now plug in y to any of the equations
5x+7(3)=6
5x+21=6
Subtract 21 from both sides
5x=-15
Divide by 5
x=-3
Your final solution is (-3,3)
