All categories

3 years ago

Which choice correctly expresses the solution set in the inequality in words?

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

6 0

Answer:

The answer to your question is letter A.

Step-by-step explanation:

Inequality x + 2 ≥ 5

Solve the inequality, remember that inequalities and equations are solved in similar ways.

- Subtract 2 in both sides

x +2 - 2 ≥ 5 - 2

- Simplify

x ≥ 3

- Remember that this sign "≥" means that x is greater or equal to a number, and this sign "≤" means that x is lower or equal to a number.

The option that satisfies our inequality is the first option.

You might be interested in

PLEASE HELP ME!!!!!!!! I WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

mars1129 [50]

A is the answer............ If you plot it on a graph, it shows a square.

5 0

3 years ago

Read 2 more answers

What is the value of R?

Vinil7 [7]

Answer:

Step-by-step explanation:

Subtract 150 from both sides

-5r ≥ -62.5

Divide both sides by -5

r ≤ 12.5

(The greater than sign flips around when you divide or multiply both sides by a negative number)

8 0

3 years ago

Read 2 more answers

Point e is the midpoint of ca and bd. which statements about the diagram are true?

defon

Answer:

Step-by-step explanation: i don’t know to be honest

8 0

2 years ago

Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?

Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

$\sin^2 \theta +\cos^2 \theta = 1$

Let us solve this equation for cosine function.

$\cos^2 \theta = 1-\sin^2 \theta$

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

$\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}$

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

$\cos \theta=\sqrt{1-\sin^2 \theta}$

Thus, the correct option is: True; quadrants I & IV

6 0

3 years ago

Read 2 more answers

What is the slope in this equation?

Elena L [17]

Answer:

3/2 looks right to me.....

6 0

3 years ago

Read 2 more answers