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2 years ago

Which choice correctly expresses the solution set in the inequality in words?

Mathematics

1 answer:

Vera_Pavlovna [14]2 years ago

6 0

Answer:

The answer to your question is letter A.

Step-by-step explanation:

Inequality x + 2 ≥ 5

Solve the inequality, remember that inequalities and equations are solved in similar ways.

- Subtract 2 in both sides

x +2 - 2 ≥ 5 - 2

- Simplify

x ≥ 3

- Remember that this sign "≥" means that x is greater or equal to a number, and this sign "≤" means that x is lower or equal to a number.

The option that satisfies our inequality is the first option.

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Pls help Pls help Pls help

Arte-miy333 [17]

Answer:

Green) 24in

Yellow) 31in

Blue) 27in

Step-by-step explanation:

Just add each number of the one shape.

To find the Area:

Multiply each number

To find Perimeter:

Add each number

4 0

3 years ago

What is an equation of the line that passes through the points (-4, 2) and (-8,3)?

inn [45]

Answer:

y = --0.25x + 1

Step-by-step explanation:

In order to find the equation of a line, you must first find the slope of the line.

The equation to find slope is $\frac{y_2 - y_1}{x_2 - x_1}$ .

Plug in the given points:

(x2, y2) = (-8,3)

(x1, y1) = (-4,2)

(y2 - y1) / (x2 - x1) = (3-1)/ (-8 - -4) = (3-2) / (-8 + 4) = 1/-4 = -0.25

Next, you solve for the y-intercept using one of the two coordinates:

y = -0.25x + b

2 = -0.25(-4) + b

2 = 1 + b

b = 2 - 1 = 1

y = -0.25x + 1

4 0

3 years ago

Math/Physics Problem (I'd be glad if you solved one of them).

Whitepunk [10]

Answer:

19.2

76.8

Step-by-step explanation:

density × volume = mass

mass = 62.4 × (pi × (40/2)² × h)

mass = 78,374.4h

WD = m×9.8×h = 9.8mh

WD = 768,069.12h²

At h = 5

WD = 768,069.12×5²

= 19,201,728 ft-lb

= 19.2 million ft-lb

At h = 10

WD = 76,806,9.12 × 10²

WD = 76,806,912 ft-lb

= 76.8 million ft-lb

4 0

3 years ago

Simplify: 7·(a+5)–30 =

postnew [5]

Answer:

7a + 5

Step-by-step explanation:

Distribute using PEMDAS.

7 0

3 years ago

Evaluate the definite integral using the graph of f(x) (Image included)

Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

$\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}$

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

$\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}$

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

$\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20$

Then by linearity, we have

$\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}$

8 0

2 years ago