We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1,
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
Answer:
The correct option is C. 14.
Step-by-step explanation:
First you have that the perimeter of a rectangle = (2·length) + (2·width)
⇒perimeter of a rectangle = [2·( x + 7)] + [2·(2x - 3)]
⇒ 32 = [2·( x + 7)] + [2·(2x - 3)] ⇒ 32 = (2x + 14) + (4x - 6)
⇒ 32 = 6x + 8 ⇒ 32 - 8 = 6x ⇒ 24= 6x ⇒ 24/6 = x ⇒ x = 4. ⇒ 3x= 12.
Answer:
தமிழ்நாட்டில் உள்ள நெல் வகைகளை குறிப்பிட்டு எழுதுக
Answer:
-1/4, 5/8
Step-by-step explanation:
:)
