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Dima020 [189]
3 years ago
14

Mark has $100,000 to invest. His financial consultant advises him to diversify his investment in three types of bonds: short-ter

m, intermediate-term, and long-term. The short-term bonds pay 4%, the intermediate-term bonds pay 5%, and the long-term bonds pay 6% simple interest per year. Mark wishes to realize a total annual income of 5.25%, with equal amounts invested in short- and intermediate-term bonds. How much should he invest in each type of bond?
Mathematics
1 answer:
galina1969 [7]3 years ago
5 0

Answer:

Short-Term investment: 5000$

Intermediate-Term investment: 65000$

Long-Term investment: 30000$

Step-by-step explanation:

To construct our first equation lets define sort-term bond investment as x, long-term investment as y.

So the equation is:

x*0,04+(100000-x-y)*0,05+y*0,06=5250

From the equation it is found that:

y=25000+x

Instead of y, if we put 25000+x the equation will be as following:

x*0,04+75000*0,05+(25000+x)*0,06=5250

From the equation it is found that:

x=5000

Short-Term investment is 5000$

x+25000=y

Long-Term investment is 30000$

Rest of the money is Intermediate-Term investment 65000$

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3 years ago
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
Someone please help me make a proof for the bottom question
Lerok [7]

Answer:

DB = CA (Proved)

Step-by-step explanation:

Statement 1.

∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2

Reason 1.  

Given

Statement 2.

Between Δ DBM and Δ CAM,  

(i) DM = CM,

(ii) ∠D = ∠C  and  

(iii) ∠DMB = ∠CMA

Reason 2.

(i) given  

(ii) given and  

(iii) ∠ DMB = ∠1 + ∠AMB and  ∠CMA = ∠2 + ∠AMB

Since ∠1 = ∠2, so, ∠DMB = ∠CMA.

Statement 3.

Δ DBM ≅ Δ CAM

Reason 3.

By angle-side-angle rule.

Statement 4.

DB = CA

Reason 4.

Corresponding sides of two congruent triangles. (Answer)

7 0
3 years ago
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