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Lesechka [4]
2 years ago
10

Help PLEASE Match the following:

Mathematics
1 answer:
Luden [163]2 years ago
3 0

Answer:

3

2

4

1

Step-by-step explanation:

mark as brain list plz and like

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Plz help 8k-- 5k combine the like terms to create a equivalent expression
Brums [2.3K]

Answer:

3k

Step-by-step explanation:

8k-5k=3k

5 0
3 years ago
Read 2 more answers
Find the next term if the sequence: 5, 5, 10, 30, 120, 600
adell [148]

Answer:

3600

Step-by-step explanation:

5 * 5 = 1

5 * 2 = 10

.

.

.

600 * 6 = 3600

5 0
3 years ago
If two pounds of meat will serve 5 people how many pounds will be needed to serve 13 people
miv72 [106K]
The answer is 5.2 pounds of meat. To find this just divide the number of people by what the information you have about servings. 13/5=2.6(number of sets), then you multiply that by how many pounds are in each set. 2.6 sets* 2 pounds per set= 5.2 pounds.
I hope this helped!
4 0
3 years ago
Thomas has $6.35 in dimes and quarters. The number of dimes is three more than three times the number of quarters. How many quar
mr Goodwill [35]

Answer:

He has 11 quarters

Step-by-step explanation:

* Lets study the information in the problem to solve it

- The value of dimes and quarters is $6.35

- There are dimes and quarters

- The dime = 10 cents

- The quarter = 25 cents

* We must change the money from dollars to cents

∵ $1 = 100 cents

∴ $6.35 = 6.35 × 100 = 635 cents

- The number of dimes = 3 + 3 × number of quarters

* Let number of dimes is D and number of quarter is Q

∴ D = 3 + 3Q

∴ 10D + 25Q = 635

* Substitute the value of D from first equation in the second equation

∴ 10(3 + 3Q) + 25Q = 635 ⇒ open the bracket

∴ 10(3) + 10(3Q) + 25Q = 635

∴ 30 + 30Q + 25Q = 635 ⇒ collect like terms

∴ 30 + 55Q = 635 ⇒ subtract 30 from both sides

∴ 55Q = 605 ⇒ divide both sides by 55

∴ Q = 11

* He has 11 quarters

5 0
3 years ago
Rewrite in simplest radical form square root of x times the fourth root of x. Show each step of your process.
Ipatiy [6.2K]

Answer:

\sqrt[4] {x^3}

Step-by-step explanation:

At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:

\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}

Alternatively, if you're allowed to use rational exponents, we can convert everything:

\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}

5 0
2 years ago
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