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3 years ago

Find (f+g)(x) if f(x)=3x+5 and g(x)=-2x^2-5x+3,

Mathematics

1 answer:

Sati [7]3 years ago

7 0

The answer is simple it is
c

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The expression 12x+8 represents the perimeter of a square write 12x+8 as a product then tell what expression represents one side

Pani-rosa [81]

Answer:

Step-by-step explanation:

Find the greatest common factor of 12x + 8

4(3x + 2) so one side is 4 and the other is 3x + 2

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2 years ago

Which expression is equivalent to 2.3 × 2.3 × 2.3 × 2.3 × 2.3?

alexdok [17]

An expression that is equivalent to 2.3 x 2.3 x 2.3 x 2.3 x 2.3 is 2.3^

5 0

3 years ago

Read 2 more answers

Please help me i really need help with this math

natima [27]

Answer:

y= 3/5x+ 6.2

Step-by-step explanation:

the slope is change in y over change in x.

-4-(-1) divided by 3-8 will be -3/-5 = 3/5

For the y-intercept, plug in x and y values. I will use (3,8).

8= 3/5(3)+b

8= 9/5+b

(subtract 9/5 from both sides)= 6 and 1/5 or 6.2 as a decimal.

6 0

3 years ago

What value of x makes this equation true? 15-7x=5x-21

belka [17]

Answer:

x=3

Step-by-step explanation:

15-7x=5x-21

12x=36

x=3

4 0

3 years ago

The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha

kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

$\mu = 3500 \times 0.0004 = 1.4$

The probability that 2 or fewer cars will be stolen is:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466$

$P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452$

$P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417$

Then:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335$

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

4 0

1 year ago