Answer:
1. 8+(30/(2+4)) = 8+(30/6) = 8+5 = 13
2. ((8+30)/2)+4 = (38/2)+4 = 19+4 = 23
Step-by-step explanation:
:)
Answer:
1. 23/20 or 1 whole and 3/20
2. 3/10
3. 4/3 or 1 whole and 1/3
4. 1/15
5. 1/2
6. 3/10
Answer:
One example is the equation:
2x + 6 = 4x/2 + 12/2
To solve this, we need to transpose like terms to the same side.
2x - 4x/2 = 12/2 - 6
2x - 2x = 6 - 6
0 = 0
Since both sides are zero, it means that the equation has infinite number of solutions.
Step-by-step explanation:
Answer:
The solution of y² - 1 = 15 is +4 and -4
Step-by-step explanation:
Given
y² - 1 = 15
Our solution goes thus;
Make y² the subject of formula
y² = 15 + 1
Add 15 to 1
y² = 16
Take square roots of both sides
√y² = √16
y = √16
Note that the square root of 16 is either +4 or -4 because +4 * +4 = 16 and -4 * -4 = 16; So, we replace √16 with ±4 which means + or -4
y = ±4
y = +4 and -4
Hence, the solution of y² - 1 = 15 is +4 and -4
9514 1404 393
Explanation:
The problem statement tells you what to do.
25^(n-1) +125 -6·5^n = 0 . . . . . subtract 6·5^n
(5^2)^(n-1) -6·5^n +125 = 0 . . . . express 25 as a power of 5
5^(2n-2) -6·5^n +125 = 0 . . . . . eliminate the double layer of exponent
(5^-2)(5^n)^2 -6·5^n +125 = 0 . . . . . use 5^n where possible
(1/25)y^2 -6y +125 = 0 . . . . . . . substitute y = 5^n
y^2 -150n +3125 = 0 . . . . . . . . . multiply by 25
_____
The applicable rules of exponents are ...
(a^b)^c = a^(bc)
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
