Identify the pair of angles as corresponding alternate interior both or neither <4,<7

A. Why does the provided equation support the fact that there is a horizontal asymptote of F(x) that is not

aniked [119]

Applying limits, it is found that since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

The function is given by:

$F(x) = \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

The horizontal asymptote is the limit of the function as x goes to infinity, hence:

$y = \lim_{x \rigtharrow \infty} F(x) = \lim_{x \rigtharrow \infty} \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

Considering only the terms with the highest exponents:

$y = \lim_{x \rigtharrow \infty} \frac{ax^2}{2x^2} = \frac{a}{2}$

Since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

For more on horizontal asymptotes and limits, you can check brainly.com/question/11598999

3 0

3 years ago

The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function?

gogolik [260]

Answer: If you plot a point in the y-axis at -6, you can plot two more points by using the slope "rise over run" Then draw a line connecting the points.

The coordinate of the y intercept is (0.-6) To find the first x values of the first 2 coordinates, add 1 then 2 to 0. To find the y values, add 2 then 4 to the -6

Step-by-step explanation:

From -6 go up 2 over 1 and plot at (1, -4 ) then up 2 over 1 again to (2, -2)

The x- intercept will be at (3,0)