<img src="https://tex.z-dn.net/?f=-24%5Cleq%203x-9" id="TexFormula1" title="-24\leq 3x-9" alt="-24\leq 3x-9" align="absmiddle" c

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ra1l [238]

3 years ago

lass="latex-formula">

Mathematics

2 answers:

dybincka [34]3 years ago

8 0

If your solving for x, you need to isolate/get the variable "x" by itself in the inequality:

-24 ≤ 3x - 9 First add 9 on both sides

-24 + 9 ≤ 3x - 9 + 9

-15 ≤ 3x Then divide 3 on both sides to get "x" by itself

$\frac{-15}{3} \leq \frac{3x}{3}$

-5 ≤ x [or x ≥ -5 if you prefer "x" to be on the left side]

BigorU [14]3 years ago

3 0

X ≥ - 5 //////////////////////////

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Given the coordinates below, what is the midpoint of AB?<br> A(-6, -10)<br> B(2,5)

madreJ [45]

Given :

$\:$

A(-6, -10)
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$\:$

$\gray{ \frak{The \: given \: two \: \: points \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}$

$\:$

Let's solve by using midpoint formula :

$\:$

$\bf \boxed{\color{red}\frak{Midpoint \: \: Formula : {( \: x ,\:y \: ) = }( \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}$

$\:$

$\large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}$

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$\: \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}$

$\:$

$\large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \cancel\frac{ -4}{2} , \cancel\frac{ - 5}{2} )}}$

$\: \:$

$\underline{ \boxed{ \large \red{ \frak{option \: d }( \frak{ - 2, - 2.5)}}}}✓$

Hope Helps! :)

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