The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
Since a(n)=-3(a(n-1)) the common ratio is -3, and a(1)=-3 so
a(n)=-3(-3^(n-1)) so the first four terms are:
-3, 9, -27, 81
Answer:
-4.6
because you add whats inside teh parenthesis then subtract by 12 before dividing by 23
The horizontal line has an equation: y = a, where a is any real number.
We know, the line passes through the point (2, 3) → x = 2, y = 3.
<h3>Answer: y = 3</h3>
