Write an equation where x

Which expression is equivalent to r^9/r^3?<br> O r^3<br> O r^6<br> O r^12<br> O r^27

valkas [14]

Answer:

r^12 no r^6

Step-by-step explanation:

I was wrong it is r^6 r−9(−3) r−9+3=r−6

r-6 becomes 1 over r6

5 0

2 years ago

Read 2 more answers

Find the width of the rectangular prism when the surface area is 208 centimeters

BlackZzzverrR [31]

Use the surface area formula of a rectangular prism to find the width. (I have changed it to use the same terms given in the problem).

A

=

2

(

d

w

+

h

w

+

h

d

)

Because of the given information, it is known that:

A

=

208

h

=

8

d

=

6

The width is not know, so let it keep it's variable

w

. But substitute the other values into the equation:

A

=

2

(

d

w

+

h

w

+

h

d

)

208

=

2

[

6

w

+

8

w

+

(

8

)

(

6

)

]

208

=

2

(

14

w

+

48

)

Use the distributive property to solve the right side of the equal sign:

208

=

2

(

14

w

+

48

)

208

=

28

w

+

96

112

=

28

w

112

28

=

w

4

=

w

The width is

4

.

5 0

4 years ago

Need help ASAP 78 points

-Dominant- [34]

Answer: 18

The original perimeter of the triangle was 12 m, so in order to find out the perimeter with the 1.5 scale factor, we must multiply 12 by 1.5, which equals 18

4 0

3 years ago

What is the expression 3r; r = 6?

rusak2 [61]

R = 6
3r = 3*6 = 18

Answer 18

6 0

3 years ago

A researcher is interested in religious differences for immigration checkpoint experiences at airports. Polling a sample of 340

vekshin1

Answer:

$z=\frac{0.52-0.46}{\sqrt{0.49(1-0.49)(\frac{1}{340}+\frac{1}{190})}}=1.325$

$p_v =2*P(Z>1.325)= 0.185$

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that we have a significant difference between the two proportions of negative experiences at 1% of significance.

Step-by-step explanation:

Data given and notation

$n_{M}=340$ sample of Muslims

$n_{C}=190$ sample of Christians

$p_{M}=0.52$ represent the proportion of Muslims with negative experience

$p_{C}=0.46$ represent the proportion of christians with negative experience

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.01$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference in the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{M} - p_{C}=0$

Alternative hypothesis: $p_{M} - p_{C} \neq 0$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{C}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{C}})}}$ (1)

Where $\hat p=\frac{p_{M}+p_{C}}{2}=\frac{0.52+0.46}{2}=0.49$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.52-0.46}{\sqrt{0.49(1-0.49)(\frac{1}{340}+\frac{1}{190})}}=1.325$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>1.325)= 0.185$

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that we have a significant difference between the two proportions of negative experiences at 1% of significance.

3 0

3 years ago