Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).

Step-by-step explanation:
Probability=
Probability for a randomly chosen girl to be senior=
Probability for a randomly chosen girl to be senior=
Probability for a randomly chosen boy to be senior=
Probability for a randomly chosen girl to be senior=
For two independent events,
Probability for both event 1 and event 2 to take place=
Since choosing boys and girls is independent,
Probability for both boy an girl chosen to be senior=
Probability for both boy and girl chosen to be senior=
So,required probability is 
Answer:
y=5
Step-by-step explanation:
7 3/10 + 6 1/3 + 2 7/10
First change them to improper fractions
73/10 + 19/3 + 27/10
now find the common denominator which would be 30
73/10 = 219 /30
19/3 = 190/30
27/10 = 81 /30
now add (219 + 190 + 81) = 490/30
now divide 490 ÷ 30 = 16 1/3
Your answer is 16 1/3
Hope this helps. :)