All categories

3 years ago

Can someone help me? I need question #23

Mathematics

1 answer:

weqwewe [10]3 years ago

8 0

Answer:

x = 3; y = 11

Step-by-step explanation:

A parallelogram has two pairs of congruent opposite sides. For quadrilateral ABCD to be a parallelogram, sides AB and CD must be congruent, and sides AD and BC must be congruent.

AB = CD

2y + 2 = 3y - 9

-y = -11

y = 11

AD = BC

3x + 6 = y + 4

We already know y = 11, so we substitute 11 for y.

3x + 6 = 11 + 4

3x + 6 = 15

3x = 9

x = 3

Answer: x = 3; y = 11

You might be interested in

Hurry please I need help on this

lubasha [3.4K]

5/6-2/5 would be my guess

beacuse i would think the answer would be 1/3 but that is not on the multiple choice.

5 0

2 years ago

Jose put$1500 into a savings account. He earns 3% interest every year. How much simple interest will he earn at the end of 3 yea

ehidna [41]

Answer

$3142

Step-by-step explanation:

8 0

3 years ago

I need help. Please

zubka84 [21]

Answer:

Answer is A.

Step-by-step explanation:

If you take the current cords of 'C' and add the cords it gives you: (4.5,-6.5). You end out with (3.5,-9,2). Hope this helps!

5 0

2 years ago

Read 2 more answers

Please help it’s finding sin C , cos C and tan C

Aloiza [94]

The given triangle has a right angle.

We use the mnemonics SOH-CAH-TOA.

1i) $\sin C =\frac{Opposite}{Hypotenuse}$ , $\implies \sin C =\frac{30}{34}$ , $\implies \sin C =\frac{15}{17}$

ii) $\cos C =\frac{Adjacent}{Hypotenuse}$ , $\implies \cos C =\frac{16}{34}$ , $\implies \cos C =\frac{8}{17}$

$\tan C =\frac{Opposite}{Adjacent}$ , $\implies \tan C =\frac{30}{16}$ , $\implies \tan C =\frac{15}{8}$

2. We want to find the hypotenuse.

We know an angle to be 23 degrees.

We were also given the side opposite to this angle to be 1200km.

Therefore we use the sine ratio.

6 0

2 years ago

Read 2 more answers

Find the equivalent exponential expression. [(-4)^5]^3

Sunny_sXe [5.5K]

Answer:

$-4^{15}$

Step-by-step explanation:

Given expression:

$\left[(-4)^5\right]^3$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies (-4)^{(5 \times 3)}$

$\implies (-4)^{15}$

$\textsf{Apply exponent rule} \quad (-a)^n=-a^n,\:\: \textsf{ if }n \textsf{ is odd}:$

$\implies -4^{15}$

4 0

1 year ago