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3 years ago

Help please...whats an explicit equation?

1 answer:

4 0

We represent a sequence with a formula that lets us find any term in the sequence without knowing any other terms, we are representing the sequence explicitly.

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What is 18.890 rounded to the nearest hundred

bagirrra123 [75]

18.90? I believe would be the answer . Let's see if someone else responds

3 0

3 years ago

Solve the equation:<br><br> (x^4 - x + y)dx - xdy=0

algol [13]

Keeping in mind that "dx" is the delta x, or differential over the x-axis, whilst "dy" is the delta y or differential over the y-axis,

$\bf (x^4-x+y)dx-xdy=0\implies \stackrel{\textit{distributing dx}}{x^4dx-xdx+ydx}-xdy=0
\\\\\\
ydx=xdy-x^4dx+xdx\implies y=\cfrac{xdy-x^4dx+xdx}{dx}
\\\\\\
y=\stackrel{\textit{distributing the denominator}}{x\cfrac{dy}{dx}-x^4+x}$

5 0

3 years ago

Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia

Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

So on this case the degrees of freedom are given by:

$df= 37+45-2=80$

And the best answer is:

d. t distribution with df = 80

5 0

3 years ago

PLZZZZZZ HELPPPPP

Makovka662 [10]

Answer:

(D)

Step-by-step explanation:

The graph shows the arm span lengths of the students, clearly we can see that the most of the students have arm span length in the initial points of the length.

Median = Middle frequency of the data. Here, median will be the length in the middle.

Mode = Most frequently occurring number in the data. Here the mode will be the length which most of the students has.

Clearly, most of the student has the length in the initial inches while the median will be in the middle.

Hence, mode will be less than the median.

8 0

3 years ago

Read 2 more answers

Find two solutions to the equation (x^3 − 64)(x^5 − 1) = 0.

Rashid [163]

Answer:

the two roots are x = 1 and x = 4

Step-by-step explanation:

Data provided in the question:

(x³ − 64) (x⁵ − 1) = 0.

Now,

for the above relation to be true the following condition must be followed:

Either (x³ − 64) = 0 ............(1)

(x⁵ − 1) = 0 ..........(2)

Therefore,

considering the first equation, we have

(x³ − 64) = 0

adding 64 both sides, we get

x³ − 64 + 64 = 0 + 64

x³ = 64

taking the cube root both the sides, we have

∛x³ = ∛64

x = ∛(4 × 4 × 4)

x = 4

similarly considering the equation (2) , we have

(x⁵ − 1) = 0

adding the number 1 both the sides, we get

x⁵ − 1 + 1 = 0 + 1

x⁵ = 1

taking the fifth root both the sides, we get

$\sqrt[5]{x^5}=\sqrt[5]{1}$

also,

1 can be written as 1⁵

therefore,

$\sqrt[5]{x^5}=\sqrt[5]{1^5}$

x = 1

Hence,

the two roots are x = 1 and x = 4

4 0

3 years ago