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andreyandreev [35.5K]
3 years ago
9

Find the solution of this system of equations - 2x + 10y = -22 -2x - 4y = 6

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0

Answer:

x = 1, y = -2

Step-by-step explanation:

- 2x + 10y = -22 _______(1)

-2x - 4y = 6 _______(2)

From (1),

10y + 22 = 2x

x = (10y + 22) / 2

x = 5y + 11 .______(3)

Substitute (3) into (2),

-2 ( 5y + 11) -4y = 6

-10y - 22 - 4y = 6

-14y = 6 + 22

-14y = 28

y = 28/ -14

y =-2

Substitute y = -2 into (3).

x = 5y + 11

x = 5(-2) + 11

x = -10 + 11

x = 1

Therefore, the solution is x = 1, y = -2.

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3 years ago
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\sqrt{4t+5}=3-\sqrt{t+5}\\\\D:4t+5\geq0\ \wedge\ t+5\geq0\ \wedge\ \sqrt{t+5}\leq3\\\\t\geq-\dfrac{5}{4}\ \wedge\ t\geq-5\ \wedge\ t\leq6

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D:x\in\left< -\dfrac{5}{4};\ 6\right>

\sqrt{4t+5}=3-\sqrt{t+5}\ \ \ |^2\\\\(\sqrt{4t+5})^2=(3-\sqrt{t+5})^2\ \ \ |use:(a-b)^2=a^2-2ab+b^2\\\\4t+5=3^2-2\cdot3\cdot\sqrt{t+5}+(\sqrt{t+5})^2\\\\4t+5=9-6\sqrt{t+5}+t+5\ \ \ \ |-t\\\\3t+5=14-6\sqrt{t+5}\ \ \ \ |-14\\\\3t-9=-6\sqrt{t+5}\ \ \ \ |change\ signs
9-3t=6\sqrt{t+5}\ \ \ \ |:3\\\\3-t=2\sqrt{t+5}\ \ \ \ |^2\\\\(3-t)^2=(2\sqrt{t+5})^2\\\\3^2-2\cdot3\cdot t+t^2=4(t+5)\\\\9-6t+t^2=4t+20\ \ \ |-4t-20\\\\t^2-10t-11=0\\\\t^2+t-11t-11=0\\\\t(t+1)-11(t+1)=0\\\\(t+1)(t-11)=0\iff t+1=0\ \vee\ t-11=0\\\\t=-1\in D\ \vee\ t=11\notin D
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