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3 years ago

Which is greater 0.03 or 0.003?

Mathematics

1 answer:

Flauer [41]3 years ago

6 0

0.03 should be the answer!

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Ejercicio de algebra. Reducir:

serg [7]

The correct answer is 1/a^7 (b)

5 0

3 years ago

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

3 years ago

A survey asked 247 students what their favorite subject was. Of those students, there were 115 boys. One hundred two students an

Butoxors [25]

Answer:

Step-by-step explanation:

you have to add a table

6 0

4 years ago

Can someone please help on these 3questions there easy I just forgot how to do it

vagabundo [1.1K]

Answer:

just plug the numbers in

Step-by-step explanation:

5 0

3 years ago

8,25,42,,<br> Sequence find the 82nd term

Citrus2011 [14]

Answer:

1385

Step-by-step explanation:

1) the difference is d=25-8=42-25=17;

the sequence given in the condition is arithmetic one (linear relationship).

2) in order to calculate the value of the 82d term:

a(n)=a(1)+d*(n-1), where n - number of required term (it is 82), then

a(82)=8+17*(82-1)=8+1377=1385.

7 0

3 years ago