Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
If you’re simplifying it’s 100x^2+200x+5
Answer:
theres nothing there
Step-by-step explanation:
Part A:
First we define the variable to be used for the problem:
x: the number of pages that Sandra should fax
The inequality for rent is:
0.06x <= 80
Note that the price will be less than using the fax from the office, since for the same number of pages, we have:
y = 0.10x
Answer:
an inequality that can be used to calculate the number of pages that Sandra should fax in a year is:
0.06x <= 80
Part B:
0.06x <= 80
From here we clear x:
x <= 80 / 0.06
x <= 1333.33333
Nearest whole number
x <= 1333
Sandra can use the leased fax for 1333 pages and the cost will be:
1333 * 0.06 = 79.98 $
Using the office fax the cost will be:
1333 * 0.1 = 133.3 $
Answer:
By renting the sara machine, you save:
133.3-79.98 = 53.32 $
