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Talja [164]
3 years ago
11

F n and m are integers and n2 m2 is even, which of the following is impossible?

Mathematics
1 answer:
iren2701 [21]3 years ago
6 0
So, I think that you mean that

n²+m² is even? (the "plus" sign is missing, but I think this is correct).

this can only happen if either:

both n and m are even
or
both n and m are odd


That's because a sum of two expressions is even if either both or none of the expressions summed is even, and a power of a number is even only if the number is even too.

are those some of the options?

yes!
<span>n and m are even,- possible!
 n and m are odd, -possible!
n+m is even, - possible; it would be the case i</span><span>f either both n and m are even or both n and m are odd n+m is odd,

so the option we'll choose is:

none of these are impossible </span><span />



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2 years ago
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sweet-ann [11.9K]

Answer:

x = 3 , y = 13

Step-by-step explanation:

Note that both equations is equal to y. Set the two equations equal to each other

y = 7x - 8; y = 5x - 2

7x - 8 = y = 5x - 2

7x - 8 = 5x - 2

Isolate the x. Subtract 5x and add 8 to both sides

7x (-5x) - 8 (+8) = 5x (-5x) - 2 (+8)

7x - 5x = -2 + 8

Simplify.

(7x - 5x) = (-2 + 8)

2x = 6

Isolate the x. Divide 2 from both sides

(2x)/2 = (6)/2

x = 6/2

x = 3

---------------------------------------------------------------------------------------------------

Plug in 3 for x in one of the equations.

y = 7x - 8

y = 7(3) - 8

Simplify. Remember to follow PEMDAS.

y = 7(3) - 8

y = 21 - 8

y = 13

---------------------------------------------------------------------------------------------------

x = 3, y = 13 is your answer

~

4 0
3 years ago
Help for a brainliest lol
Sergio [31]

Step-by-step explanation:

The answer is option b.

Explanation in the pic.

Need any other maths, feel free!!

6 0
3 years ago
Read 2 more answers
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