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Goshia [24]
3 years ago
11

3 packs of soda cost 10 dollars less than 5 packs of soda. How much does one pack of soda cost?

Mathematics
1 answer:
Nikolay [14]3 years ago
3 0
3s = 5s - 10
-2s = -10
S = 5

S is the cost per pack in dollars
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a bag contains 4 red marbles and 3 blue marbles. Another bag contains 7 green marbles and 6 yellow marbles. You randomly pick on
Irina18 [472]

Answer: 18/91 or ≈ 0.2

Step-by-step explanation:

Bag one: 4 red + 3 blue = 7 total

Bag two: 7 green + 6 yellow = 13 total

probability of picking blue from first bag: 3/7

probability of picking yellow from second bag: 6/13

3/7*6/13 = 18/91 or about 0.2 chance

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2 years ago
Draw the image of the figure after a rotation of 180° around 0. Can anyone help?
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Https://us-static.z-dn.net/files/d32/38c3ab868a9002a8c0889292f96a8840.jpeg

6 0
3 years ago
The cost of six hens and one duck at the university poultry farm is GH₵40. While four hens and three ducks cost GH₵36. What is t
Anon25 [30]

Answer:

Step-by-step explanation:

Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.

The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.

The system is

6h + 1d = 40

4h + 3d = 36

The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,

1d = 40 - 6h.

Now that we know what d equals, we can sub it into the second equation where we see a d. In order,

4h + 3d = 36 becomes

4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!

4h + 120 - 18h = 36 and

-14h = -84 so

h = 6.

That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:

1d = 40 - 6(6) and

d = 40 - 36 so

d = 4.

That means that each duck costs $4.

3 0
3 years ago
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
Find an equation of the plane that is parallel to the xz-plane and is located 11 units to the right of the xz-plane in standard
mina [271]

Answer:

y = 11

Step-by-step explanation:

Since our plane is parallel to the xz plane, the x and z are independent of each other, i.e. they could be anything. So xz plane has an equation of y = 0. So if this plane is located 11 units to the right of the xz plane then its equation must be y = 11.

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3 years ago
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