Read Out

Mathematics

1 answer:

kap26 [50]2 years ago

5 0

Answer:

pov: im getting free points

Step-by-step explanation:

You might be interested in

Please help I give you 30 points

valentinak56 [21]

Answer:

The last one, 14 3/4

Step-by-step explanation:

I hope this helped :)

4 0

2 years ago

Plz answer only if correct :)) <br> (this is trig.ratios) in

slamgirl [31]

Answer:

Step-by-step explanation:

Since you want to find the variable x all you have to do is simple subtraction.

The two numbers (61 and 22). Subtract those numbers and you get 39. Now it wants you to round to the jearest hundredth but there is no hundreds place so we can round to the nearest tenth. Which would be 30! Hope it helped... :)!

bye

8 0

3 years ago

Suppose that, after measuring the duration of many telephone calls, a telephone company found their data was well-approximated b

Musya8 [376]

Answer:

a) 7.79%

b) 67.03%

c) Cumulative Distribution Function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

Step-by-step explanation:

We are given the following in the question:

$p(x) = 0.1 e^{-0.1x}$

where x is the duration of a call, in minutes.

a) P( calls last between 2 and 3 minutes)

$=\displaystyle\int^3_2 p(x)~ dx\\\\= \displaystyle\int^3_20.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^3_2\\\\=-\Big[e^{-0.3}-e^{-0.2}\Big]\\\\= 0.0779\\=7.79\%$

b) P(calls last 4 minutes or more)

$=\displaystyle\int^{\infty}_4 p(x)~ dx\\\\= \displaystyle\int^{\infty}_40.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^{\infty}_4\\\\=-\Big[e^{\infty}-e^{-0.4}\Big]\\\\=-(0- 0.6703)\\= 0.6703\\=67.03\%$

c) cumulative distribution function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

6 0

3 years ago

150 students were surveyed on how many text messages to send in a date for different devices. let X represent the number of stud

kakasveta [241]

Given that the total number of students that sent messages = 150 students

a) To obtain the equation to represent the number of students who send text messages, we will sum up the variables in the Venn diagram and equate it to 150.