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Mathematics

2 answers:

STatiana [176]3 years ago

8 0

Answer:

It is $66.50 cheaper to purchase a return trip ticket than it is to purchase 2 one-way tickets.

Step-by-step explanation:

It is asking us how much does 2 one-way tickets costs as opposed to a return trip ticket. First, let's figure out how much does 2 one-way tickets cost.

Equation:

287.75 x 2 = 575.50

2 one-way tickets cost $575.50.

Then, to find the difference, subtract the return trip cost from the two one-way tickets.

Equation: 575.50 - 509.00 = 66.50

The difference between the two is $66.5

Conclusion: It is $66.50 cheaper to purchase a return trip ticket than it is to purchase 2 one-way tickets.

I hope this helps!

PilotLPTM [1.2K]3 years ago

3 0

Answer:

$ 66.50 cheaper

Step-by-step explanation:

A one way ticket cost $287.75 so two one way tickets cost $575.50. A return trip costs $509.00. 575.50-509.00=66.50

Therefore a return trip is $66.50 cheaper than two one way trip tickets. :))) <3

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Angelina_Jolie [31]

Answer:

110.5348 minutes

Step-by-step explanation:

The difference from room temperature changes from 103 to 59 in 46 minutes, so that difference can be modeled by the exponential equation ...

Δt = 103×(59/103)^(t/46)

We want to find t for the temperature difference Δt = 91 -64 = 27.

27 = 103×(59/103)^(t/46)

27/103 = (59/103)^(t/46) . . . . . divide by 103

Taking logs gives the linear equation ...

log(27/103) = (t/46)log(59/103)

Multiplying by the inverse of the coefficient of t, we get ...

t = 46·log(27/103)/log(59/103) ≈ 46·(-0.58147346)/(-0.24198521)

≈ 110.5347

It will take about 110.5347 minutes for the turkey to cool to 91 °F internally.

_____

Comment on 4 decimal places

An answer correct to 4 decimal places (7 significant digits) is a pretty good indication that the problem was worked correctly. However, that level of precision in the timing makes little sense in this context. Most thermometers will take at least a few seconds to register the temperature to within a tenth of a degree or so. This problem is asking for an answer that is within 6 milliseconds and 30 micro-degrees. Neither of these is anywhere near realistic for a kitchen meat thermometer.

More realistic would be an answer to 4 significant figures, a tenth of a minute and a few hundredths of a degree.

(The rate of change at the time of interest is about -0.33 degrees per minute.)