Given h(t)=-2(t+5) squared +4, find h(-8)

2 answers:

6 0

Hey there,

Lets solve this together,

Simplify

$h(t) = -2(t + 5)^2 + 4

h(-8) = -2(-8 + 5)^2 + 4

h(-8) = -2(-3^2) + 4

h(-8) = -2(9) + 4

h(-8) = -18 + 4

h(-8) = - 14$

DerKrebs [107]3 years ago

4 0

H(t) = -2(t + 5)^2 + 4
h(-8) = -2(-8 + 5)^2 + 4
h(-8) = -2(-3^2) + 4
h(-8) = -2(9) + 4
h(-8) = -18 + 4
h(-8) = - 14

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