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3 years ago

Tell whether the two quantities vary directly. Explain your reasoning. The cafeteria provides three meals per day.

Mathematics

1 answer:

Dafna11 [192]3 years ago

3 0

Answer:

The cafeteria provides three meals per day.

Reason 1

Yes, they vary directly

As number of days increases ,Total number of meals i.e

1st day ⇒ 3

2nd day⇒6

3 rd day⇒9

4th day⇒12

......................

.........................

increases.

Total number of Meals = k×Number of days

But there is another possibility also

Reason 2

1 st day ⇒ 3

2nd day ⇒3

3rd day⇒ 3

.....................

As you can see from the above expression On each day number of meals is

constant.

So we can say that ,

On each Day=Constant amount of meal=3

So, there is no Proportionality between Days and Meal.

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Answer:

45/126 or 5/14

Step-by-step explanation:

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1 year ago

Read 2 more answers

Whats its the result Of 25099.506/4.45?

777dan777 [17]

$\dfrac{25099.506}{4.45} \ \text{Divide}$

Shift the decimal points of both 25099.506 and 4.45 to the right by 2 decimal places.

(This is needed to convert 4.45 to 445, since long division must divide by a whole number.)

$\text{Set up the long division.}
$

$\text{Calculate 2509 divided by 445, which is 5 with a remainder of 284.}$

 $\text{ Bring down 9, so that 2849 is large enough to be divided by 445.}$

$\text{Calculate 2849 divided by 445, which is 6 with a remainder of 179.} 
$

$\text{Bring down 5, so that 1795 is large enough to be divided by 445.}$

$\text{Calculate 1795 divided by 445, which is 4 with a remainder of 15.}$

$\text{Bring down 06, so that 1506 is large enough to be divided by 445.
}$

$\text{Calculate 1506 divided by 445, which is 3 with a remainder of 171.}$

$\text{Bring down 0, so that 1710 is large enough to be divided by 445.}$

$\text{Calculate 1710 divided by 445, which is 3 with a remainder of 375.}$

$\text{Bring down 0, so that 3750 is large enough to be divided by 445.}$

$\text{Calculate 3750 divided by 445, which is 8 with a remainder of 190.}$

$\text{Bring down 0, so that 1900 is large enough to be divided by 445.}$

$\text{Calculate 1900 divided by 445, which is 4 with a remainder of 120.}$

$\text{Bring down 0, so that 1200 is large enough to be divided by 445.}$

$\text{Calculate 1200 divided by 445, which is 2 with a remainder of 310.}$

Therefore, 25099.506 ÷ 4.45 ≈ 5640.33842

8 0

3 years ago

Can anyone pls help me to solve question 2 f and g and pls provide me a explanation I’m with that questions for three days

zvonat [6]

Answer:

f) a[n] = -(-2)^n +2^n

g) a[n] = (1/2)((-2)^-n +2^-n)

Step-by-step explanation:

Both of these problems are solved in the same way. The characteristic equation comes from ...

a[n] -k²·a[n-2] = 0

Using a[n] = r^n, we have ...

r^n -k²r^(n-2) = 0

r^(n-2)(r² -k²) = 0

r² -k² = 0

r = ±k

a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q

We find p and q from the initial conditions.

f) k² = 4, so k = 2.

a[0] = 0 = p + q

a[1] = 4 = -2p +2q

Dividing the second equation by 2 and adding the first, we have ...

2 = 2q

q = 1

p = -1

The solution is a[n] = -(-2)^n +2^n.

g) k² = 1/4, so k = 1/2.

a[0] = 1 = p + q

a[1] = 0 = -p/2 +q/2

Multiplying the first equation by 1/2 and adding the second, we get ...

1/2 = q

p = 1 -q = 1/2

Using k = 2^-1, we can write the solution as follows.

The solution is a[n] = (1/2)((-2)^-n +2^-n).

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2 years ago