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likoan [24]
3 years ago
5

How does a fetus receive nutrients before birth?

Biology
2 answers:
Leto [7]3 years ago
8 0
Through the blood vessels in the umbilical cord, the fetus receives all the necessary nutrition, oxygen, and life support from the mother through the placenta.
MAXImum [283]3 years ago
5 0
From the mother through the placenta
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One anatomical difference between cercopithecoids and hominoids is:
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What characteristic makes osmosis different from diffusion?
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Most plant proteins do not match our needs for essential amino acids and therefore are called _______________ proteins.
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(e) Predict the effect of the removal of the final electron acceptor on the rate of carbon fixation by the chloroplast. Justify
Vinil7 [7]

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The ATPs produced during Chemeiosmosis, in the chloroplast is needed during Calvin cycle to fix carbon for production of CHO, protein and fats  during conversion of 3C-glyceride phosphate(GP) to 2C- triose phosphate.(TP) .

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Therefore, if the final electron acceptor is removed, there will be no electron transport chains which generated the PMF, for pumping H+ across into the thylakoid membrane of the chloroplast, to generate the electrochemical gradients, needed for  the energy for ATPase synthase enzymes,to synthesize ATPs production.

Therefore, the removal of the electron acceptor (oxygen) leads to stoppage of electron transport chain, and hence loss of ATP s, and therefore, no Carbon fixation as CHO, or protein, or fats.

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7 0
3 years ago
A pure-breeding fruit fly with the recessive mutation cut wing, caused by the homozygous cc genotype, is crossed to a pure-breed
insens350 [35]

Answer:

1. 0% of probability, 2. 50% of probability, 3. 75% of probability.

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In order to find the probabilities we have to draw Punnet squares.  The mutated gene will be symbolized with a *.

1. Male CC with female CC, there is no mutation, the probability will be 0%.

         X           Y

X   ║   XX   ║  XY

X   ║  XX    ║  XY  

2. The male has not got a mutation and the female has. When we draw the Punnet square, with one female X mutated, we find that there is a 50% of probability of mutation.

         X            Y

X* ║  X*X    ║  X*Y

X   ║  XX     ║ XY

3. Now both, the female and the male, has the mutation. When we draw the Punnet square with mutations in  the female and in the male, we find that there is a 75% of probability of  mutation.

       X*             Y

X* ║ X*X*    ║   X*Y

X  ║  XX*    ║  XY

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