I have 30 ones, 82 thousnads, 4 hundred thousands, 60 tens and 100 hundreds. what am I?

Find the value of x. M M (2x 10) (2x + 40) N X=

Lady_Fox [76]

Answer:

Could you state the question in the correct order?? Like is N supposed to be there?

7 0

2 years ago

What pair of numbers has the geometric mean of 44

PSYCHO15rus [73]

Basically any two numbers whose product is 44^2 = 1936.
so 16×121 = 1936
so the pair is 16 and 121

6 0

3 years ago

In a plot of probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum

Lunna [17]

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

<h3>What is an electron?</h3>

The electron is a subatomic particle with a negative one elementary charge electric charge.
Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.

Electron in the hydrogen:

Hydrogen has the simplest electron configuration to write because it just contains one electron.
There is essentially only one electron surrounding the Hydrogen nucleus.
Because hydrogen only has one electron, its configuration is 1s1.
The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.

Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

Know more about electrons here:

brainly.com/question/860094

#SPJ4

The complete question is given below:

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:

A. at a0. the first Bohr radius

B. at slightly less than a0

C. at slightly more than a0

D. at 2 a0

E. at a0/2

6 0

1 year ago

During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were

Triss [41]

Question

During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were: A. Desserts B. Appetizers C. entrees

Answer:

A)Desserts = 25 %

B)Appetizers = 32.5 %

C)Entrées = 32.5 %

Step-by-step explanation:

Given:

Number of appetisers = 13

Number of entrees = 17

Number of desserts = 10

A. percentage of the dishes he delivered were Desserts

Percentage of Desserts = $\frac{\text{ Number of dessert}}{\text{ total number of dishes}} \times 100$

Total number of dishes = 13 + 17 + 10 = 40

Percentage of Desserts = $\frac{10}{40} \times 100$

Percentage of Desserts = $0.25 \times 100$

Percentage of Desserts = 25 %

B. percentage of the dishes he delivered were Appetizers 

Percentage of Desserts = $\frac{\text{ Number of Appetizers }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{13}{40} \times 100$

Percentage of Desserts = $0.325 \times 100$

Percentage of Desserts = 32.5 %

C. percentage of the dishes he delivered were Entrées 

Percentage of Desserts = $\frac{\text{ Number of Entrees }}{\text{ total number of dishes}} \times 100$

Percentage of Desserts = $\frac{17}{40} \times 100$

Percentage of Desserts = $0.425 \times 100$

Percentage of Desserts = 42.5 %

7 0

3 years ago

Please helpp me i need a answer

Lesechka [4]

Answer:

0.0005123

Step-by-step explanation:

The scientific notation 5.123e-4 is same as 5.123×10^-4 or 5.123×10-4. Thus, to get the answer to 5.123e-4 as a decimal, we multiply 5.123 by 10 to the power of -4.

= 5.123e-4

= 5.123 × 10-4

= 0.0005123

7 0

2 years ago