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dybincka [34]
3 years ago
8

Pls help ASAP!I will mark u brainliest, and pls answer correctly or I will report u

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

Step-by-step explanation:

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Log2+ log8=2<br><br>how do I do it?​
soldi70 [24.7K]

Answer:

Step-by-step explanation:

log(2)+log(8) = 2

1.20412≠2

False

8 0
3 years ago
I NEED HELP (GONE WRONG) (NOT CLICKBAIT)
const2013 [10]

Answer:

Overhand Throw

Step-by-step explanation:

The ball is thrown over the shoulder so it is considered an overhand throw. Plus they only use an underhand and sidearm in baseball.

3 0
3 years ago
Read 2 more answers
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
2 years ago
Can someone help me please
goldenfox [79]

Answer:

1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}

Step-by-step explanation:

The applicable rule is ...

  x^{\frac{m}{n}}=\sqrt[n]{x^m}

It works both ways, going from radicals to frational exponents and vice versa.

The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.

7 0
3 years ago
V=3.14(r)^2h solve for r
sveticcg [70]
Assuming the h is not in the exponent, R would equal The square root of V over 3.14h 
6 0
3 years ago
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