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Oxana [17]
3 years ago
11

Solve for q; 6n-5q/11t = c

Mathematics
1 answer:
Ghella [55]3 years ago
7 0

Answer:

\large\boxed{q=\dfrac{6n-11ct}{5}}

Step-by-step explanation:

\dfrac{6n-5q}{11t}=c\qquad\text{multiply both sides by}\ 11t\neq0\\\\6n-5q=11ct\qquad\text{subtract}\ 6n\ \text{from both sides}\\\\-5q=11ct-6n\qquad\text{change the signs}\\\\5q=6n-11ct\qquad\text{divide both sides by 5}\\\\q=\dfrac{6n-11ct}{5}

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If there is a 4 digit code and using the digits 1-4, how many possibilities are there?
timurjin [86]

Answer:

64

Step-by-step explanation:

1

2

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3, 2

3, 4

4, 1

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4, 3

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1, 3, 2

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2, 4, 3

3, 1, 2

3, 1, 4

3, 2, 1

3, 2, 4

3, 4, 1

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4, 1, 3

4, 2, 1

4, 2, 3

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4, 3, 2

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2, 3, 4, 1

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2, 4, 3, 1

3, 1, 2, 4

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3, 2, 1, 4

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3 0
3 years ago
Read 2 more answers
Is this a function or no
blondinia [14]

Answer:

Yes

Step-by-step explanation:

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4 0
3 years ago
Evaluate 5c+cd when c=1/5 and d=15
oee [108]
5*1/5+1/5*15=4
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This should equal 4 if I did this correctly.
4 0
3 years ago
Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent. How many text messag
professor190 [17]

Given that Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent.

Kimora's cell phone bill for one month is $52.

We need to determine the number of text messages Kimora sent for one month.

Also, we need to write and equation and solve it.

<u>The equation:</u>

Let x denote the number of text messages Kimora sent for one month.

Thus, the equation is given by

35+0.05x=52

Therefore, the equation for the number of text messages Kimora sent for one month is 35+0.05x=52

<u>Solving the equation:</u>

We need to solve the equation 35+0.05x=52

Subtracting both sides of the equation by 35, we get;

0.05x=17

Dividing both sides of the equation by 0.05, we get;

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Therefore, the number of messages sent is 340.

3 0
3 years ago
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arsen [322]

0=40-10t-5t^2

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t=-4 (not a solution) or t=2

Answer: after 2 seconds

7 0
3 years ago
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