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Naya [18.7K]
3 years ago
10

If you know that 4 of an item cost a certain amount, and you want to find out what one costs, which operation will you use?

Mathematics
1 answer:
Roman55 [17]3 years ago
4 0
Division because actually i dont know but its division
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The school band collected $2,892 for 480 tickets sold to their spring concert. Adult tickets were $8 each and student tickets we
kakasveta [241]
A + s = 480......s = 480 - a
8a + 5s = 2892

8a + 5(480 - a) = 2892
8a + 2400 - 5a = 2892
8a - 5a = 2892 - 2400
3a = 492
a = 492/3
a = 164 <=== there were 164 adult tickets sold
5 0
3 years ago
Read 2 more answers
The circumference of a circular painting is
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Divide 28.26 by 3.14

The answer is 9
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3 years ago
Khan academy how to find the domain of a function equation.
alexira [117]

Answer:

I cant even see anything can you reupload your answer, please?

Step-by-step explanation:

5 0
3 years ago
1. Let a; b; c; d; n belong to Z with n &gt; 0. Suppose a congruent b (mod n) and c congruent d (mod n). Use the definition
lukranit [14]

Answer:

Proofs are in the explantion.

Step-by-step explanation:

We are given the following:

1) a \equi b (mod n) \rightarrow a-b=kn for integer k.

1) c \equi  d (mod n) \rightarrow c-d=mn for integer m.

a)

Proof:

We want to show a+c \equiv b+d (mod n).

So we have the two equations:

a-b=kn and c-d=mn and we want to show for some integer r that we have

(a+c)-(b+d)=rn. If we do that we would have shown that a+c \equiv b+d (mod n).

kn+mn   =  (a-b)+(c-d)

(k+m)n   =   a-b+ c-d

(k+m)n   =   (a+c)+(-b-d)

(k+m)n  =    (a+c)-(b+d)

k+m is is just an integer

So we found integer r such that (a+c)-(b+d)=rn.

Therefore, a+c \equiv b+d (mod n).

//

b) Proof:

We want to show ac \equiv bd (mod n).

So we have the two equations:

a-b=kn and c-d=mn and we want to show for some integer r that we have

(ac)-(bd)=tn. If we do that we would have shown that ac \equiv bd (mod n).

If a-b=kn, then a=b+kn.

If c-d=mn, then c=d+mn.

ac-bd  =  (b+kn)(d+mn)-bd

          =    bd+bmn+dkn+kmn^2-bd

          =           bmn+dkn+kmn^2

          =            n(bm+dk+kmn)

So the integer t such that (ac)-(bd)=tn is bm+dk+kmn.  

Therefore, ac \equiv bd (mod n).

//

3 0
3 years ago
What numbers add up to equal -25?
vlabodo [156]
-29 + 4
-28 + 3
-27 + 2
-26 + 1
-24 + -1
-23 +-2
-22 +-3
-21 +-4
-20 +-5
-19 +-6
-18 +-7
....
8 0
3 years ago
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