Use rounding or compatible numbers to estimate the sum. 222+203
2 answers:
The sum of 222 + 203 by using rounding to compatible number is 420
<h3>Further explanation</h3>Rounding results on integers can be used to estimate or determine the results of a calculation. Estimates can be used as a reference or comparison in determining the truth of the results of a calculation
To rounding integers to the nearest hundreds, look at the tens
1. If the tens are less than 5 (1-4), then the unit number is omitted
Example: 735 ---> 700
2. If the tens are 5 to 9 then the tens are rounded up to 1 hundred
Example: 279 ----> 300
Whereas compatible numbers are the numbers that are easy to add, subtract, multiply, or divide. The value of Compatible numbers will be close to the actual numbers
So We can round the numbers to the nearest ten, hundred, etc. to make them compatible numbers
In the summation operation above we will round out the numbers:
- 1. number 222
we round the number to the nearest ten become 220
- 2. number 203
we round the number to the nearest ten become 200
So the sum results become:
220 + 200 = 420
<h3>Learn more</h3>Describe how to round 678 to the nearest hundred
Rounding to the nearest hundredth of a meter.
Round 32,697 to the nearest tenth, hundredth, and one.
Keywords: rounding, nearest ten, addition operation
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The complete question in the attached figure
we have that
f(x) = x²<span> + 1
g(x) = x – 4
step 1
find </span>(f o g)(x)
(f o g)(x)= (x - 4)² + 1(f o g)(x) = x² - 8x + 16 + 1
(f o g)(x) = x² - 8x + 17
step 2
find (f o g)(10)
(f o g)(10) = 10² - 8*(10) + 17
(f o g)(10 = 100 - 80 + 17
(f o g)(10)= 37
the answer is 37
we have that
f(x) = x²<span> + 1
g(x) = x – 4
step 1
find </span>(f o g)(x)
(f o g)(x)= (x - 4)² + 1(f o g)(x) = x² - 8x + 16 + 1
(f o g)(x) = x² - 8x + 17
step 2
find (f o g)(10)
(f o g)(10) = 10² - 8*(10) + 17
(f o g)(10 = 100 - 80 + 17
(f o g)(10)= 37
the answer is 37
We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is <span>5 feet. </span>
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is <span>5 feet. </span>