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Gwar [14]
3 years ago
7

Please help me everytime I post this no one helps :( and I need this done soon

Mathematics
2 answers:
AnnZ [28]3 years ago
7 0

Answer:

Its should be 1 because the graph shows you thats its 1

sasho [114]3 years ago
3 0
1 I think. Tell me if that is correct
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Find the sum of the first 7 terms of the series.
Flura [38]

Answer:

C.258

Step-by-step explanation:

6-12+24-48+96-192+384

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3 years ago
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What is 2/5 divided by 5/7 in fraction form, not decimal
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Ok. In order to do this set up 2/5 divided by 5/7. The way you divide with fractions is by multiplying them but flipping the second fraction into 7/5 <---this is known as the reciprocal. In other words do:

2/5 x 7/5 =
14/25
There you go.
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3 years ago
Consider this sphere inside the cylinder. A sphere is inside of a cylinder with a same radius and height. Which statements are t
sashaice [31]

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A,C,E

Step-by-step explanation:

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Simplify the expression below and write it as a single logarithm:
OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

<u>Solution:</u>

Given, expression is 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

Rearranging the terms we get,

\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)

\text { since a } \times \log b=\log \left(b^{a}\right)

\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)

\text { We know that } \log a \times \log b=\log a b

\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.

\text { We know that } \log a-\log b=\log \frac{a}{b}

\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

Hence, the simplified form \rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

4 0
3 years ago
Read 2 more answers
1. y = x2 + 2x – 8<br><br> Axis of Symmetry:<br><br> Vertex:<br><br> Domain:<br><br> Range:
valentinak56 [21]

Answer:

Axis of Symmetry: x=-1

Vertex: (-1,-9)

Domain:   (- ∞ ,∞ )

Range: (-9,∞ )

Step-by-step explanation:

6 0
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