This number is written in extended form. Each multiplication determines the place the digit is in the number you have to determine.
4*100 → This indicates that the first digit of the number is in the place of the "hundreds", if you solve the multiplication the result is 400
2*10 → This multiplication indicates that the second digit of the number is in the place of the "tens", the result of the multiplication is 20
4*1 → This multiplication indicartes that the third digit of the number represents the "units", te result of the multiplication is 4
After the units you have to put the decimal point and all digits below it will be decimal values.
7*(1/10) → The first digit after the decimal point is in the "tenths" place, you can write it as 0.7
7*(1/100) → This indicates that this digit is in the second place after the decimal dot, in the "hundredths" place, you can write it as 0.07
0*(1/1000)→ The multiplication indicates that the digit is in the third place after the decimal dot, in the "thousands" place, you can write it as 0.000
To write the number in decimal form you have to put each digit in their given order, or add the result of each multiplicatin toghether:
400+20+4+0.7+0.07+0.000
424.770
1. X(0,0) --> X'(3,-5).
To go from (0,0) to (3,-5), you must go to the right 3 and down 5.
I cannot answer 2 or 3, as rotations are not my strong suit.
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Try The 3rd one I know it’s right
Answer:
how about no
Step-by-step explanation:
did anyone ask