Isn’t this just 20m? Or is it a trick question and I’m just not getting it?
Arman (10m) Babken (10m) Cecilia
Answer:
there u go
Step-by-step explanation:
Hope It helps u ....
Answer:
xn = n·(n + 1)/2
Step-by-step explanation:
Answer:
540
Step-by-step explanation:
3% of 6000 is 180. Multiply that by 3 years and you have your result.
The first term of the arithmetic progression exists at 10 and the common difference is 2.
<h3>
How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8
5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
brainly.com/question/1486233
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