Answer:
1680 ways
Step-by-step explanation:
Total number of integers = 10
Number of integers to be selected = 6
Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.
<u>2 ways</u> <u>1 way</u> <u> </u> <u> </u> <u> </u> <u> </u>
Each of the line represent the digit in the integer.
After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840
Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways
Therefore, there are 1680 ways to pick six distinct integers.
Answer: answer is in picture. :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference
we have
Let
The common difference is 
We can write an Arithmetic Sequence as a rule
where
a_n is the nth term
d is the common difference
a_1 is the first term
n is the number of terms
Find the 63rd term of the arithmetic sequence
we have
substitute
Answer:2284
Step-by-step explanation:
13% of what is 78
"what" is the unknown, so use x for what.
"of" in math usually means a multiplication.
"is" means "="
13% * x = 78
0.13x = 78
x = 78/0.13
x = 600
Answer: the number is 600
