The area of a circle A equals either:
πr² or πd²/4
96 = πd²/4 => d = 11 inches
The diameter of the second circle equals :
11*1.5 = 16.5 inches
The area equals: π(16.5)²/4 = 214 square inches
Good luck
Answer
-3
+
+16=0
Step-by-step explanation:
Answer:
m>=-6
Step-by-step explanation:
m+5>=-1
m>=-1-5
m>=-6
The sum of the squares of their ages is; 5x²
<h3>How to Solve Algebraic Word Problems?</h3>
We are told that Maria is twice the age of Miriam.
Now, of the age of Miriam is x, then we can say that;
Age of Mariam = x
Age of Maria = 2x
Now, we want to find the sum of the squares of their ages. Thus, this is expressed as;
x² + (2x)²
= x² + 4x²
= 5x²
Read more about Algebraic Word Problems at; brainly.com/question/13818690
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The complete question is;
Express in algebraic language: the sum of the squares of the ages of Maria and Miriam, if it is known that Maria is twice the age of Miriam.
<span>Simplifying
(6a + -8b)(6a + 8b) = 0
Multiply (6a + -8b) * (6a + 8b)
(6a * (6a + 8b) + -8b * (6a + 8b)) = 0
((6a * 6a + 8b * 6a) + -8b * (6a + 8b)) = 0
Reorder the terms:
((48ab + 36a2) + -8b * (6a + 8b)) = 0
((48ab + 36a2) + -8b * (6a + 8b)) = 0
(48ab + 36a2 + (6a * -8b + 8b * -8b)) = 0
(48ab + 36a2 + (-48ab + -64b2)) = 0
Reorder the terms:
(48ab + -48ab + 36a2 + -64b2) = 0
Combine like terms: 48ab + -48ab = 0
(0 + 36a2 + -64b2) = 0
(36a2 + -64b2) = 0
Solving
36a2 + -64b2 = 0
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '64b2' to each side of the equation.
36a2 + -64b2 + 64b2 = 0 + 64b2
Combine like terms: -64b2 + 64b2 = 0
36a2 + 0 = 0 + 64b2
36a2 = 0 + 64b2
Remove the zero:
36a2 = 64b2
Divide each side by '36'.
a2 = 1.777777778b2
Simplifying
a2 = 1.777777778b2
Take the square root of each side:
a = {-1.333333333b, 1.333333333b}</span>
