The answers are 0 and 2
This can be found by looking at the x axis and finding every point where the line crosses
<h3 /><h3>

</h3>
Equation for Perimeter of a rectangle: Perimeter = 2W + 2L
<h3>Defining the variables, let</h3>
<h3>Width = x</h3><h3>Length = 2x+3 (3 more than twice the width)</h3>
<h3>Plugging everything into the equation</h3>
<h3>30= 2(x) + 2(2x+3) using the distributive property,</h3>
<h3>30=2x+4x+6 combining like terms</h3>
<h3>30=6x+6 subtracting 6 from both sides,</h3>
<h3>24=6x divide both sides by 6</h3>
<h3>4=x This means that the width is 4 m.</h3>
<h3>To get the length, use the expression L=2x+3 and plug in x = 4 that was already solved for</h3>
<h3>L=2(4)+3</h3>
<h3>L=8+3 = 11 m</h3>
<h3>So the dimensions of the rectangle are width is 4 m and length is 11 m.</h3>
Distribute and combine like-terms!
-4x + 12x - 2x - 2
6x - 2
Answer:
x -2y = -4
Step-by-step explanation:
The slope of the line between points C and D is ...
m = (y2 -y1)/(x2 -x1)
m = (7 -13)/(5 -2) = -6/3 = -2
The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...
y -k = m(x -h) . . . . line with slope m through point (h, k)
y -1 = 1/2(x -(-2))
We can rearrange this to standard form.
2y -2 = x +2 . . . . . multiply by 2
-4 = x -2y . . . . . . . subtract 2y+2
x -2y = -4 . . . . . . standard form equation of the desired line
Answer:
CBA is a secant.
Step-by-step explanation: