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3 years ago

What is the LCM of 2.2 and 5 ?

Mathematics

1 answer:

Kamila [148]3 years ago

3 0

Do you mean 22? if so, it is 110 because 110= 22 * 5

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5 less than a number is equivalent to 1 more than three times the number<br><br> The number is ??

givi [52]

Answer:

-3

Step-by-step explanation:

Let x equal the mystery number

Our equation will be:

x - 5 = 1 + 3x

Subtract x from both sides

-5 = 1 + 2x

Subtract 1 from both sides

-6 = 2x

Divide both sides by 2

-3 = x

4 0

3 years ago

How do I write this expression:The quantity seven plus Z, squared

Dmitry_Shevchenko [17]

Answer:

(7+Z)²

Step-by-step explanation:

A less ambiguous way to describe the quantity might be "the square of the quantity seven plus Z".

As it is, we rely on the presence of the comma to tell us that the quantity to be squared is (7+Z). If the comma were not present, we would assume you want to add 7 to the square of Z: 7+Z².

the quantity 7 plus Z: (7+Z)

that quantity squared: (7+Z)²

6 0

2 years ago

The following system has a solution of x=-5, y=9, z=11.

Bess [88]

False - plug in the bramble for the first equation and you get 40 = 12 which is not true

7 0

2 years ago

Write the equation of a line perpendicular to y= -5/6x-3 and whose y-intercept is (0,11).

worty [1.4K]

Answer:

y=6/5x+11

Step-by-step explanation:

Perpendicular lines have the opposite sign and reciprocal of the original line. Since the y-intercept is 11 we know that it is 6/5x+11

8 0

2 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

3 years ago