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umka2103 [35]
3 years ago
8

Solve the equation and give me how you solved it and the answer

Mathematics
1 answer:
Viktor [21]3 years ago
4 0
Multiplying both sides by 3, we get (3/9)*(2m-16)=(2m+4). Next, we multiply both sides by 9 and expand to get 6x-48=18m+36. Subtracting 6x and 36 from both sides, we get 12x=-48-36=-84. After that, we divide both sides by 12 to get m=-7
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If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. see if those v
kkurt [141]

a=4 , b=3  These values make the equation true .

<u>Step-by-step explanation:</u>

Here we have , If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. We need to find if those values make the equation true . Let's find out:

We have the following equation:

-(a/b) = (-a)/b = a/(-b) , Let a=4 , b=3 , So

⇒ -(a/b) = (-a)/b = a/(-b)

⇒ -\frac{a}{b} = \frac{-a}{b} = \frac{a}{-b}

⇒ -\frac{4}{3} = \frac{-4}{3} = \frac{4}{-3}

⇒ -\frac{4(-1)}{3} = \frac{-4(-1)}{3} = \frac{4(-1)}{-3}                   { Multiplying by -1 }

⇒ \frac{4}{3} = \frac{4}{3} = \frac{4}{3}

Therefore , These values make the equation true .

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