108 you don't need the distributive property.
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
20
Step-by-step explanation:
2 1/2 = 5/2
5/2 x 4/1 = 20/1 = 20
(We are dividing fraction)
(keep change flip)
Answer:
The y-coordinate of their intersection point is 3
That is y=3
Step-by-step explanation:
Given two lines are y=6x+15 and y=mx+4
Given that the two lines intersect at x=-2
To find the y coordinate of their intersection point :
Equating the two lines
6x+15=mx+4
6x+15-mx-4=0
6x-mx+11=0
(6-m)x+11=0
At x=-2 (6-m)x+11=0
(6-m)(-2)+11=0
(6-m)(-2)=-11
Substitute the value in y=mx+4 we get
At x=-2 
Therefore y=3
Therefore the y-coordinate of their intersection point is 3
Circumference of a circle is 2πr where r is radius of a circle.
2*3.14*7=43.96 almost 44 inches in whole number where π=3.14
