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maxonik [38]
3 years ago
11

1. Simplify. 4(2a - 1) - 4 + 7a ​

Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer:

<em><u>=15a−8</u></em>

Step-by-step explanation:

Let's simplify step-by-step.

4(2a−1)−4+7a

Distribute:

=(4)(2a)+(4)(−1)+−4+7a

=8a+−4+−4+7a

Combine Like Terms:

=8a+−4+−4+7a

=(8a+7a)+(−4+−4)

=15a+−8

Answer:

=15a−8

hope i helped

-lvr

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The radius of a circle is 4 in . Find it’s circumference in terms of
luda_lava [24]

Answer:

8pi

Step-by-step explanation:

The formula for circumference is the radius multiplied by 2\pi. In this case, 4\cdot 2\pi=8\pi. Hope this helps!

6 0
3 years ago
What value of n makes the equation true? -2n + 1.8 =3.2
stich3 [128]

Answer:

-0.7

Step-by-step explanation:

-2n+1.8=3.2

-2n=3.2-1.8

-2n=1.4

n=1.4/-2

n=-0.7

4 0
3 years ago
PLS help me Order four and seven tenths repeating, negative four and eight ninths, 490%, and −4.9 from least to greatest.
Digiron [165]

The order from least to greatest negative four and seven tenths repeating, negative four and eight ninths, 490%, and −4.9 from least to greatest is; option A

  • −4.9,
  • negative four and eight ninths
  • four and seven tenths repeating
  • 490%,

<h3>Ascending order</h3>

four and seven tenths repeating

= 4.77777777

negative four and eight ninths

= -4 8/9

= -4.888888888888888

490%

= 490/100

= 4.9

−4.9

Rearranging from least to greatest (ascending order)

  • -4.9
  • -4.888888888888888
  • 4.77777777
  • 4.9

Learn more about ascending order;

brainly.com/question/12783355

#SPJ1

6 0
2 years ago
4) Solve for x: 4(2x - 10) = 12x + 10
Lera25 [3.4K]

Answer:

x=-25/2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

10x - 11 = 8x + 23

Subtract 8x from both sides

10x - 11 - 8x = 8x + 23 - 8x

2x - 11 = 23

Add 11 to both sides

2x - 11 + 11 = 23 + 11

2x = 34

Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

x = 17

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0
3 years ago
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