Triangle ABC has vertices of A(–6, 7), B(4, –1), and C(–2, –9). Find the length of the median from A) 4 b) square Root of 18
C) 8
D) Square root of 68
1 answer:
We know that
the median<span> is the segment that joins each vertex with the midpoint of the opposite side</span>
using a graph tool
see the attached figure
Step 1
Find the midpoint segment BC
<span>B(4, –1), and C(–2, –9)
</span>
Xm=(4-2)/2=1
Ym=(-1-9)/2=-5
the midpoint BC is (1,-5)
the length of median is the distance point A(-6,7) and midpoint BC (1,-5)
d=√(12²+7²)=√193=13.89 units
the answer is 13.89 units
the median<span> is the segment that joins each vertex with the midpoint of the opposite side</span>
using a graph tool
see the attached figure
Step 1
Find the midpoint segment BC
<span>B(4, –1), and C(–2, –9)
</span>
Xm=(4-2)/2=1
Ym=(-1-9)/2=-5
the midpoint BC is (1,-5)
the length of median is the distance point A(-6,7) and midpoint BC (1,-5)
d=√(12²+7²)=√193=13.89 units
the answer is 13.89 units
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The capital formation of the investment function over a given period is the
accumulated capital for the period.
- (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.
- (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.
Reasons:
(a) The given investment function is presented as follows;
(a) The capital formation is given as follows;
From the end of the second year to the end of the fifth year, we have;
The end of the second year can be taken as the beginning of the third year.
Therefore, for the three years; Year 3, year 4, and year 5, we have;
The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87
(b) When the capital stock exceeds $100,000, we have;
Which gives;
The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.
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