Ask question

Ask question

All categories

3 years ago

13

Simplify.

}" alt="\sqrt{\frac{18}{50} }" align="absmiddle" class="latex-formula">

2 answers:

VARVARA [1.3K]3 years ago

6 0

Answer:

3/5 or 0.6 or 6% depends on what your asking for

Step-by-step explanation:

^2 sqrt 0.36 = 0.6

STALIN [3.7K]3 years ago

3 0

$Answer: \\ \sqrt{ \frac{18}{50} } = \sqrt{ \frac{9}{25}} = \sqrt{ \frac{ {3}^{2} }{ {5}^{2} } } = \frac{3}{5}$

You might be interested in

Cody stamped 460 envelopes in 30 minutes. How many envelopes per minute did Cody stamp?

Leokris [45]

Answer:

15 1/3 envelopes in 1 minutes

Step-by-step explanation:

Take the number of envelopes and divide by the number of minutes

460 envelopes / 30 minutes

15.333333.... envelopes per minute

15 1/3 envelopes in 1 minutes

3 0

3 years ago

33°<br> (3m + 3)<br> ent OR Vertical_<br> Angle Relationship: Complementary OR Supplementary

Reptile [31]

Answer:

complementary

Step-by-step explanation:

because the angles add up to 90°

3 0

3 years ago

Factor completely 6x^2 -4x

Liono4ka [1.6K]

Answer:

2x(3x−2)

Step-by-step explanation:

Factor $6x^{2}$ − 4x

$6x^{2}$ − 4x

=2x(3x−2)

Hope this helps!

4 0

3 years ago

The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All

Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

$Pr(A)=\dfrac{11}{36}$ - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

$Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.$

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

$Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.$

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

$Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.$

4 0

3 years ago

Which is greater, 13/35 or 2/5?

zhenek [66]

Hi there!

If you run into problems like this, remember to "Stay calm and find the common denom." That just means find the common denominator.

13/35 and 2/5 = 13/35 and 14/35

As you can tell, 2/5 is larger.

Hope this helps.

:)

5 0

3 years ago