Answer:
L(x,y) = (2,-8,0) + (0,-1,1)*t
Step-by-step explanation:
for the planes
x + y + z = -6 and y + z = -8
the intersection can be found subtracting the equation of the planes
x + y + z - ( y + z ) = -6 - (-8)
x= 2
therefore
x=2
z=z
y= -8 - z
using z as parameter t and the point (2,-8,0) as reference point , then
x= 2
y= -8 - t
z= 0 + t
another way of writing it is
L(x,y) = (2,-8,0) + (0,-1,1)*t
is the square of
. That is:
.
.