The population of a town increased from 10,550 to 16,275. What was the approximate percent of increase?

PLEASE HELP ME WITH MY QUESTIONS I REALLY NEED HELP!!!! ANSWER IF YOU ACTUALLY KNOW.

stira [4]

Answer:

i think its a

Step-by-step explanation:

(sry if im wrong)

6 0

3 years ago

Express the null hypothesis and the alternative hypothesis in symbolic form. Use the correct symbol ( μ, rho, σ) for the indicat

ipn [44]

Answer:

c) H0 : p = 5.8%

H1 : p > 5.8%

Step-by-step explanation:

At the null hypothesis, we test that the percentage is equal to a certain value. At the alternate hypothesis, we have a test about this percentage, if it is more, less, or different from the tested value.

A psychologist claims that more than 5.8 percent of the population suffers from professional problems due to extreme shyness

At the null hypothesis, we test if the percentage is 5.8%

$H_0: p = 5.8\%$

At the alternate hypothesis, we test if this percentage is more than 5.8%. So

$H_a: p > 5.8\%$

This means that the correct answer is given by option c.

3 0

3 years ago

Read 2 more answers

What is the area of something that is 2 inches long and 5/6 inches wide

Free_Kalibri [48]

Area = Length x Width

The Length is 2 inches
The Width is 5/6 inches

2 * (5/6) = 10/6

simplify and you get....
5/3

5 0

3 years ago

What is the solution set of the equation x^2 - 7x - 18 = 0

photoshop1234 [79]

(x-9)(x+2)=0
x=9 or x=-2

3 0

3 years ago

Read 2 more answers

Evaluate the integral by making an appropriate change of variables.

VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

u = y + x

v = y - x

Solving for x and y, we would have

x = (u - v)/2

y = (u + v)/2

in which case the Jacobian and its determinant are

$J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12$

The trapezoid R has two of its edges on the lines x + y = 8 and x + y = 9, so right away, we have 8 ≤ u ≤ 9.

Then for v, we observe that when x = 0 (the lowest edge of R), v = y ; similarly, when y = 0 (the leftmost edge of R), v = -x. So

-x ≤ v ≤ y

-(u - v)/2 ≤ v ≤ (u + v)/2

-u + v ≤ 2v ≤ u + v

-u ≤ v ≤ u

So, the integral becomes

$\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du$

$=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du$

$=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du$

$=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}$

4 0

3 years ago