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ankoles [38]
3 years ago
5

Please help me! Only have about 10 minutes until I have to submit this assignment!

Mathematics
2 answers:
salantis [7]3 years ago
8 0

Answer:

626

Step-by-step explanation

irinina [24]3 years ago
4 0
The answer is 626 I think
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Factor completely 2x5 + 10x4 − 22x3.
Luba_88 [7]

Given equation is :

2x^{5}+10x^{4}-22x^{3}=0

Taking out 2x^{3} common we get,

x^{2}+5x-11=0

Now solving this we get,

As 11 is not factor-able, we will solve it using the formula,

x=\frac{-b+\sqrt{b^{2}-4ac}}{2a}

a=1 b=5 and c=-11

we get,

x=\frac{-5+\sqrt{69} }{2} and x=\frac{-5-\sqrt{69} }{2}

5 0
3 years ago
Read 2 more answers
What is the slope of this line? ​
Vedmedyk [2.9K]

Answer:

upward?

Step-by-step explanation:

5 0
3 years ago
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Is 1.2/3 and 1.8/ 4/5 proportional
Stella [2.4K]

Answer:

No

Step-by-step explanation:

1.2/3 =0.4

4/5 can be written as 0.8

So, 1.8/0.8 = 2.25.

However, 1.8/4/5 is the same as:

1.8/1 ÷ 4/5

Keep Change Flip

1.8/1 x 5/4 = 9/4

(1.8 x 5=9 & 1 x4 =4)

9/4 =2.25

3 0
3 years ago
What is thr inverse of f(x) if the function is x=-4,-2,0,2,4 f(x)=-2,-1,0,1,2
Lorico [155]
For a function, if it has an inverse function, keep in mind that, the "domain of the original, is the range of the inverse, and the range of the original, is the domain of the inverse", what the dickens does that mean?

well, it means the values for "x" and f(x), on the inverse, are the same values, but swapped up, therefore

\bf \stackrel{original~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-4&-2\\
-2&-1\\
0&0\\
2&1\\
4&2
\end{array}}\qquad \qquad \qquad 
\stackrel{inverse~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-2&-4\\
-1&-2\\
0&0\\
1&2\\
2&4
\end{array}}
7 0
3 years ago
Drag each tile to the correct location. Not all tiles will be used.
Novosadov [1.4K]

Answer:

25:64

Step-by-step explanation:

surface : 4×pi×R^2

R1 = 5x

R2 =8x

4piR1^2 / 4piR2^2 = R1^2/R2^2 = 5x^2/8x^2 = 25x^2/64x^2 = 25/64

4 0
3 years ago
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