We need the square and the lengths of it to help you
We can reduce the fraction by dividing
the numerator and denominator by 3
and get our simplified answer
<span>=<span>51 ÷ 3/54 ÷ 3</span>=<span>17/<span>18
The </span></span></span>Answer:
<span>=<span>17/<span>18
</span></span></span>
If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Learn more about equation here
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9x+1+32x+1=36
Combine like terms
41x+2=36
Subtract 2 from both sides
41x=34
X= 41/34 or 1.2
Since the exponent (-3) is negative, flip the expression to: 1/(5n^4)^3.
Notice how the negative exponent becomes positive as you flip it.
Now evaluate the powers in the denominator: 1/((5^3)(n^4)^3
I separated the constant (5) from the variable (n) to show you how the powers are evaluated.
1/(5x5x5)(nxnxnxn)(nxnxnxn)(nxnxnxn)
—-> the power four means that there are 4 multiples of n in the parentheses. The power 3 corresponds to how many groups.
1/(125)(n^12)
= 1/125n^12
