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faust18 [17]
3 years ago
10

Micah was asked to add the following expressions:

Mathematics
1 answer:
scZoUnD [109]3 years ago
3 0

Given expression: \frac{3x^2-x-9}{x^2+3x+2}+\frac{-2x^2+2x+5}{x^2+3x+2}


We need to add the given rational expressions.


First step: Combined like terms in the numerator and kept the common denominator.


\frac{3x^2-x-9-2x^2+2x+5}{x^2+3x+2} =\frac{x^2+x-4}{x^2+3x+2}


Second step they applied : Canceling the like term x^2 and got \frac{x-4}{3x+2}.

Note: We can't cancel like terms in top and bottom like this.

We can cancel out common factors in top an bottom.

<h3>Therefore, Micah did not add the expressions correctly.</h3>
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EXPLANATION

The given function is
f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40

According to the remainder theorem,

f( - 6) = R
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We therefore substitute the value of x and evaluate to obtain,

f( - 6) =  { (- 6)}^{4}  + 8 {( - 6)}^{3}  + 10 { (- 6)}^{2}  - 7( - 6)+ 40




f( - 6) =  1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40




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This will evaluate to,


f( - 6) =  10


Hence the value of the function when
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is
10



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10
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f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40
is divided by
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