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faust18 [17]
4 years ago
10

Micah was asked to add the following expressions:

Mathematics
1 answer:
scZoUnD [109]4 years ago
3 0

Given expression: \frac{3x^2-x-9}{x^2+3x+2}+\frac{-2x^2+2x+5}{x^2+3x+2}


We need to add the given rational expressions.


First step: Combined like terms in the numerator and kept the common denominator.


\frac{3x^2-x-9-2x^2+2x+5}{x^2+3x+2} =\frac{x^2+x-4}{x^2+3x+2}


Second step they applied : Canceling the like term x^2 and got \frac{x-4}{3x+2}.

Note: We can't cancel like terms in top and bottom like this.

We can cancel out common factors in top an bottom.

<h3>Therefore, Micah did not add the expressions correctly.</h3>
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Answer:

4/11

Step-by-step explanation:

The sample space is (6,1),(6,2),(6,3),(6,4),(6,5)(2,6),(1,6),(3,6)(4,6),(5,6),(6,6). The Favorable outcome is (6,1),(6,2),(2,6) and(1,6). The probability is 4/11=4/11

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The question is how many out of 12 is 1/4? We can do this in a couple of ways. First, set up this equation:

x/12 = 1/4

Solve it by multiplying both sides by 12:

x/12 = 1/4
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3 years ago
If the mass of the
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3 years ago
I have a two digit number the sum of the digits is 12 the first digit is 4 Less Than 3 times the second what is my number​
nignag [31]

Answer:

84

Step-by-step explanation:

Let the first digit = x

Let the second digit =y

x + y = 12

x + 4 = 3*y

===========

From the second equation, we learn that x = 3y - 4

Put that into the first equation.

3y - 4 + y = 12          Combine the left side

4y - 4 = 12                Add 4 to both sides

4y = 16                     Divide by 4

4y/4 = 16/4        

y = 4  

=================

x + 4 = 12

x + 4 - 4 = 12-4

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3 0
3 years ago
Given the Production Function Q = 72X + 15X 2 - X 3 , where Q =Output and X=Input (5 marks) a) What is the Marginal Product (MP)
rusak2 [61]

Answer:

a.) Marginal Product (MP) = 120

b.) Average Product = 126

c.) At x = 12, the output is maximum.

d.) After 5 levels of inputs diminishing returns set in.

Step-by-step explanation:

Given that,

Q = 72x + 15x² - x³

a.)

Marginal Product is equal to

\frac{dQ}{dx} = 72 + 30x - 3x^{2}

At x = 8

MP = 72 + 30(8) - 3(8)²

     = 72 + 240 - 192

     = 120

∴ we get

Marginal Product (MP) = 120

b.)

Average Product is equals to

= \frac{Q}{x}

= 72 + 15x - x²

At x = 6

Average Product = 72 + 15(6) - 6²

                             = 72 + 90 - 36

                             = 126

∴ we get

Average Product = 126

c.)

For Maximizing Q,

Put \frac{dQ}{dx} = 0

⇒72 + 30x - 3x² = 0

⇒24 + 10x - x² = 0

⇒x² - 10x - 24 = 0

⇒x² - 12x + 2x - 24 = 0

⇒x(x - 12) + 2(x - 12) = 0

⇒(x + 2)(x - 12) = 0

⇒x = -2, 12

As items can not be negative

∴ we get

At x = 12, the output is maximum.

d.)

Now,

For Diminishing Return

\frac{d(MP)}{dx} = \frac{d^{2}Q}{dx^{2} }   < 0

⇒30 - 6x < 0

⇒-6x < -30

⇒6x > 30

⇒x > 5

∴ we get

For x > 5, the diminishing returns set in

i.e.

After 5 levels of inputs diminishing returns set in.

3 0
3 years ago
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