We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
(16n + 5) / (2)
Evaluating again for n = inf:
(16 (inf) + 5) / (2) = inf
Therefore, the limit tends to infinity.
Answer:
d.limit does not exist
You know you have to draw the triangles right?
Solution :
Given :
X = the number of boys in a family of four children
Families having four children are chosen randomly.
The gender distribution in the four child family are equally probable.
Thus,
X P(X) CDF
0 
= 1/16 
1 
= 1/4 
2 
= 3/8 
3 
= 1/4 
4 
= 1/16 1
You can write this two ways - as a list of prime factors, or combine like factors and represent their quantity with an exponent.
If you begin by dividing by two, you can do that six times, with a three as the remaining prime factor.
2·2·2·2·2·2·3
OR
2∧6 · 3
Answer:
63cm²
Step-by-step explanation:
Area of the shaded region = Area of the rectangle - Area of the two triangles
Area of the rectangle = 6(3+14)
Area of the rectangle = 6 * 17
Area of the rectangle = 102cm²
Area of the smaller triangle = 1/2 * 3 * 6
Area of the smaller triangle = 18/2 = 9cm²
Area of the larger triangle = 1/2 * 6 * (17-7)
Area of the larger triangle = 1/2 * 6 * 10
Area of the larger triangle = 60/2 = 30cm²
Area of the shaded part = 102 - (9+30)
Area of the shaded part = 102 - 39
Area of the shaded part = 63cm²
