Which expression is best represented by the number line model

Let’s assume that human body temperatures are normally distributed with a mean of 98.20° F and a standard deviation of 0.62° F.

uysha [10]

Answer: It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

Step-by-step explanation:

Since we have given that

Mean = 98.20°F

Standard deviation = 0.62°F

If Bellevue Hospital in New York City uses 100.6°F as the lowest temperature considered to be a fever.

So, $\bar{X}=100.6^\circ F$

So, using the normal distribution, we first find the value of z.

$z=\dfrac{\bar{x}-\mu}{\sigma}\\\\x=\dfrac{100.6-98.2}{0.62}\\\\z=3.87$

Since z = 3.87

So, p = 0.0001 =0.1%

So,It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

4 0

3 years ago

Pls help<br><br> Given: △ABC, CM⊥ AB, BC = 5, AB = 7<br> CA = 4 sqrt(2)<br> Find: CM

babymother [125]

Answer:

The general plan is to find BM and from that CM. You need 2 equations to do that.

Step One

Set up the two equations.

(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32

BM^2 + CM^2 = 5^2 = 25

Step Two

Subtract the two equations.

(7 - BM)^2 + CM^2 = 32

BM^2 + CM^2 = 25

(7 - BM)^2 - BM^2 = 7 (3)

Step three

Expand the left side of the new equation labeled (3)

49 - 14BM + BM^2 - BM^2 = 7

Step 4

Simplify And Solve

49 - 14BM = 7 Subtract 49 from both sides.

-49 - 14BM = 7 - 49

- 14BM = - 42 Divide by - 14

BM = -42 / - 14

BM = 3

Step Five

Find CM

CM^2 + BM^2 = 5^2

CM^2 + 3^2 = 5^2 Subtract 3^2 from both sides.

CM^2 = 25 - 9

CM^2 = 16 Take the square root of both sides.

sqrt(CM^2) = sqrt(16)

CM = 4 < Answer

Step-by-step explanation:

6 0

2 years ago

In a basketball game, Team A defeated Team B with a score of 97 to 63. Team A won by scoring a combination of two-point baskets,

-BARSIC- [3]

Answer:

14 free throw baskets , 25 two point baskets and 11 three point baskets

Step-by-step explanation:

Let n₁ represent the number of free-throw baskets, n₂ represent the number of two point baskets and n₃ represent the number of three point baskets.

Now, from the question, the number of two point baskets, n₂ is greater than the free throw baskets by 11. This is written as n₂ = n₁ + 11. Also, the number of three point baskets n₃ is three less than the number of free point baskets. This is written as n₃ = n₂ - 3. Since our total number of points equals 97, it follows that, sum of number of points multiplied by each point equals 97. So, ∑(number of points × each point) = 97. Thus,

n₁ + 2n₂ + 3n₃ = 97. Substituting n₂ and n₃ from above, we have n₁ +2(n₁ + 11) + 3(n₁ - 3) = 97.

Expanding the brackets, we have, n₁ + 2n₁ + 22 + 3n₁ - 9 = 97

collecting like terms, we have 6n₁ + 13 = 97

6n₁ = 97 - 13

6n₁ = 84

dividing through by n₁ we have, n₁ = 84/6 =14

so n₁ our free throw baskets equals 14. Substituting this into n₂ our number of two point baskets equals n₂ = n₁ + 11 = 14 + 11 = 25. Our number of three point baskets n₃ = n₁ - 3. So, n₃ = 14 -3 = 11.

7 0

2 years ago

Read 2 more answers

Diego inicia un viaje por carretera de 12 horas con la batería de su teléfono al 75%. Dado su uso normal, ¿su teléfono durará to

faltersainse [42]

Based on Diego's normal usage of his phone, if the battery is at 75%, the phone will not last the whole trip.

<h3>How long will the phone battery last?</h3>

First find out how long each percentage of battery life lasts:

= 15 / 100

= 0.15 hours

If Diego is going on a 12 hour trip with 75%, the length of time it would last is:

= 0.15 x 75

= 11.25 hours

This is less than the 12 hours required so the phone will not last the whole trip.

Rest of question:

At 100%, the battery can go for 15 hours.

Find out more on rate of use at brainly.com/question/16140581.

#SPJ1

3 0

1 year ago

Comprei uma bola futebol por R$16,00 e uma bola de basquete por R $9,00. Qual é o preço médio dessas duas bolas?

sukhopar [10]

O preço médio é de R$12,50.

7 0

2 years ago